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3 years ago

Does anyone know this?

Mathematics

1 answer:

yulyashka [42]3 years ago

8 0

Thus is an example of Foil problems

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Can someone help me please?

stich3 [128]

Have you tried asking a teacher for help before this

and did you try to take notes cuse notes are your best friends

6 0

2 years ago

Read 2 more answers

How do you do it?I'm lost

Leto [7]

Answer and Step-by-step explanation:

The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.

Q's x and y are 1 , 1

R's x and y are 1 , 5

T's x and y are 5 , 1

S's x and y are 5 , 5

Now what you do is use the translation on all of these values.

Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)

R's x and y turns into -6 , 6

T's x and y are -2 , 2

S's x and y are -2 , 6

You can then plot the points on the graph and connect the lines to complete the reflection.

Hope this helps ! !

4 0

3 years ago

I have assessment quiz please

alekssr [168]

Answer:

A&B

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.......

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7 0

2 years ago

The angle of elevation from a buoy in the water to the top of a lighthouse is 68degrees. If a buoy is 300 ft from the base of th

Katen [24]

Answer:

The height of the lighthouse is $742.5\ ft$

Step-by-step explanation:

Let

h -----> the height of the lighthouse

we know that

The tangent of angle of 68 degrees is equal to divide the height of the lighthouse by the horizontal distance from the buoy to the base of lighthouse

$tan(68\°)=\frac{h}{300}$

Solve for h

$h=(300)tan(68\°)=742.5\ ft$

7 0

3 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

3 years ago