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3 years ago

Solve -6 |10x+4|-2=-26

Mathematics

1 answer:

sladkih [1.3K]3 years ago

5 0

Answer:

x=0 or x= −4 /5

Step-by-step explanation:

Add 2 to both sides

Divide both sides by -6

And then solve the absolute value

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A college student is taking two courses. The probability she passes the first course is 0.67. The probability she passes the sec

andrezito [222]

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We can solve this question treating the probabilities as a Venn set.

I am going to say that:

Event A: She passes the first course.

Event B: She passes the second course.

The probability she passes the first course is 0.67.

This means that $P(A) = 0.67$

The probability she passes the second course is 0.7.

This means that $P(B) = 0.7$

The probability she passes at least one of the courses is 0.79.

This means that $P(A \cup B) = 0.79$

a. What is the probability she passes both courses

This is $P(A \cap B)$ .

We use the following relation:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.67 + 0.7 - 0.79 = 0.58$

0.58 = 58% probability she passes both courses

5 0

3 years ago

Use the discriminant to find the number of real solutions of the equation 3x2 – 5x + 4 = 0. Show your work.

abruzzese [7]

So the equation to find the discriminant is $b^2-4ac$ , with a = x^2 coefficient, b = x coefficient, and c = constant. Using that formula, our equation is $(-5)^2-4*3*4$

Firstly, solve the exponent and multiplications: $25-48$
Next, do the subtraction, and your discriminant is -23.

Now because the discriminant is less than zero, there are no real solutions.

8 0

4 years ago

What is the sum of squares for factor b for this anova procedure?

mestny [16]

The answer is 160

hope it will be help ( ´ ▽ ` )ﾉ

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3 years ago

Which expression is equivalent to 5(9 + 7)? 14 + 12 14 + 7 45 + 7 45 + 35

nika2105 [10]

5(9 + 7) = 5 x 9 + 5 x 7 = 45 + 35

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4 years ago

A letter of the alphabet used to represent numbers is called

hoa [83]

A variable

......................

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3 years ago