I’m sorry, I wish I knew this one and I would help
Answer:
.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.
Step-by-step explanation:
Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...
Step-by-step explanation:
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Answer:
Option A
Triangles ABC and TUV
Step-by-step explanation:
Given three triangles ABC , FGH and TUV
For triangles ABC and FGH, given that
DF =AB
DH = AC
and angle F = angle A
This cannot be taken as SAS congruence because the angle F is not included between the equal sides. Two triangles can be congruent by SAS only if two sides and included angle are congruent.
For triangles ABC and TUV we have AB=TU, AC = TV and
included angles between these sides are equal.
So these two triangles are congruent
We write corresponding sides only in order Hence ABC = TUV
and Not VTU =ABC
So option A is true.
Answer:
9
Step-by-step explanation:
Because line PQ and line PR are both tangent to circle S, it would result in them being equal. So first to find PQ, you would have to find the value of variable x. To do this you would set both equations equal to each other and solve
6x - 9 = 2x + 3
-2x -2x
4x - 9 = 3
+9 +9
4x = 12
x = 3
Now you have to substitute 3 back into the equation for PQ:
6(3) - 9
18 - 9
= 9
Resulting in PQ = 9, to check your answer, take the value of x (3) and substitute it into PR and you should also get 9
2(3) + 3
6 + 3
= 9