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Margaret [11]
2 years ago
8

(Please someone help me!) (No links!)

Mathematics
1 answer:
Tems11 [23]2 years ago
3 0
40.00- 28.8% = 28 so it is 28.8% !!!!
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3/5 / 6 show ur work
faltersainse [42]

Answer:

\frac{1}{10}

Step-by-step explanation:

\displaystyle \frac{\frac{3}{5} }{6}

\frac{3}{5\times \:6}

\frac{3}{30}

=\frac{1}{10}

4 0
4 years ago
Read 2 more answers
Identify the lateral area and surface area of a regular triangular pyramid with base edge length 14 cm and slant height 15 cm
posledela

Answer:

D) L = 315 cm2 ; S = 399.9 cm2

Step-by-step explanation:

Lateral area;

3 × (½)(14)(15)

315 cm²

Surface area:

315 + (½)(14)(14)sin(60)

399.8704896 cm²

6 0
3 years ago
Read 2 more answers
∫∫x²(y-x)dxdy ,d là miền giới hạn bởi các đường y=x² và x=y²
Valentin [98]

It looks like the integral is

\displaystyle \iint_D x^2 (y-x) \,\mathrm dx\,\mathrm dy

where <em>D</em> is the set

<em>D</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ 1 and <em>x</em> ² ≤ <em>y</em> ≤ √<em>x</em>}

So we have

\displaystyle \iint_D x^2(y-x)\,\mathrm dx\,\mathrm dy = \int_0^1 \int_{x^2}^{\sqrt x} x^2(y-x)\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \left(\frac{x^2y^2}2-x^3y\right)\bigg|_{y=x^2}^{y=\sqrt x} \\\\ = \int_0^1 \left(\frac{x^3}2-x^{7/2}+x^5-\frac{x^6}2\right)\,\mathrm dx \\\\ = \left(\frac{x^4}8 - \frac{2x^{9/2}}9 + \frac{x^6}6 - \frac{x^7}{14}\right)\bigg|_{x=0}^{x=1} = \frac18-\frac29+\frac16-\frac1{14} = \boxed{-\frac{1}{504}}

5 0
3 years ago
Solve for x. <br><br> −2 = 3/9x
dlinn [17]

Answer: -6 That’s your answer.

3 0
3 years ago
Ed's new car has a value of $23,500, but it is expected to depreciate at a rate of 7.5% per year. If you were to write an expone
Delicious77 [7]

Answer:

0.925 or 92.5%

Step-by-step explanation:

y=a(1-b)^x

decay factor is 1-b <- and the part we care about

b is 7.5%=0.075

1-0.075

=0.925

I'm a little rusty on exponential rates, but I hope this helps!

3 0
3 years ago
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