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Margaret [11]
2 years ago
8

(Please someone help me!) (No links!)

Mathematics
1 answer:
Tems11 [23]2 years ago
3 0
40.00- 28.8% = 28 so it is 28.8% !!!!
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Karim wants to buy a shirt that normally sells for $46.50. It is on sale for One-third off. How much does Karim need to pay to b
Volgvan

Answer:

Step-by-step explanation:

First I took the original price of the shirt (46.50) since it is going one third off I divided it by 3 (46.50/3=15.50)

I took away the one third I divided from it (46.50-15.50=31)

I got 31 dollars as my final answer.

Now Karim needs to buy the shirt for $31.

8 0
3 years ago
Read 2 more answers
I need help plz real onez plz
melamori03 [73]
The mean is 10.
To find the mean you add up all the numbers and divide by how many sets of numbers there were.
8+10+11+8+13=50
50/5=10.
6 0
2 years ago
Read 2 more answers
Mrs. Kwan
9966 [12]

One and a half gallons. (1.5 gallons)

3 0
3 years ago
Use the given confidence interval limits to find the point estimate p^ and the margin of error E. 0.325
diamong [38]

Answer:

0.350

Step-by-step explanation:

Confidence interval = point estimate ± margin of error

Point estimate = Confidence interval - margin of error

To get the margin of error, we will take the average of the difference of the interval given. Given the confidence interval 0.325<p<0.375

Margin of error = 0.375-0.325/2

Margin of error = 0.050/2

Margin of error = 0.025

Using the interval of 0.375

Point estimate = 0.375 - 0.025

Point estimate = 0.350

3 0
3 years ago
The probabilty of getting an A in math is 0.65 and the probability of getting an a in science is 0.62 whats the probability of g
ruslelena [56]

Answer:

The probability of getting an a in both courses is 1.27

Step-by-step explanation:

Probability of getting A in Math, P(M) = 0.6 5

Probability of getting A in Science, P(S) = 0.62

Required probability of getting A in both courses, P(M and S)

= P(M) + P(S)

= 0.65 + 0.62

= 1.27

6 0
3 years ago
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