Step-by-step explanation:
a) Jill ended her scooter at her house
b) 2/3 or 0.67
c) The domain is [0,19] , The domain tell about the Elapsed Time of the Jill's scooter ride
d) The range is [2,6] , The range tell about the Distance travelled from Jill's House
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Answer:
B. 11
Step-by-step explanation:
Set up a system of equations where a is the number of adults and c is the number of children
a + c = 87
8a + 5c = 468
Solve by substitution by rearranging the first equation, then substituting it in the second equation:
a = 87 - c
Substitute this for a in the second equation, then solve for c:
8(87 - c) + 5c = 468
696 - 8c + 5c = 468
696 - 3c = 468
-3c = -228
c = 76
Then, plug this into the first equation to solve for a:
a + c = 87
a + 76 = 87
a = 11
So, 11 adults attended the carnival.
The correct answer is B, 11
Check out the attached image below. Use polynomial long division (see figure 1) or synthetic division (figure 2) to find that the quotient is x-8
This tells us the slant asymptote is y = x-8
The presence of the slant asymptote means we do not have a horizontal asymptote. As x gets larger and larger, and heads to infinity, then y approaches the line y = x-8; rather than y approaching some single fixed value.
The vertical asymptote is x = -4 because this x value makes the denominator x+4 equal to 0. We cannot divide by zero.
Figure 3 shows the graph, which I have done using GeoGebra (a free graphing tool). This is also attached below.
Answer:
20
Step-by-step explanation:
We're king of shown that it's a parallelogram, so we should assume LM = KN (we can't solve it if we don't know if it's a parallelogram).
LM = KN
3x - 4 = x + 12
2x = 16
x = 8
LM = x + 12 = 8 + 12 = 20
KN = 3x - 4 = 3*8 - 4 = 24 - 4 = 20
checks out
The weight of Euclid is 10.625 pounds, and the weight of Riemann is 21.25 pounds.
- <em>Let the current weight of Euclid = x</em>
- <em>Let the current weight of Pythagoras = T</em>
- <em>Let the January weight of Pythagoras = y</em>
The expression that represents the given scenario is written as;
- when Pythagoras lost 13 pounds: T = y - 13
- when Pythagoras gains 1.2 times Euclid's weight: = T + 1.2x
when Pythagoras weight is 1/4 pound less than weight in January:
T + 1.2x + 0.25 = y
y- 13 + 1.2x + 0.25 = y
1.2x - 12.75 = 0
Euclid's weight is calculated as follows;
1.2x = 12.75
The weight of Riemann is calculated as follows;
Learn more about word problem to algebra here: brainly.com/question/21405634