7.158 * 10^9 rounds to 7 * 10^9
7 * 10^9 = 7,000,000,000
Vicki ate 5/20 cookies on Friday and 15/20 last week
Christy c = 90 min
kids k = 120 min
total time t = ?
I would do : 90+120 = 210 then divide that by 2 which equals 105 min
Num. 4 no because 5t2 doesn't equal 10 …or equals7
![(x-r_1)(x-r_2)=x^2-(r_1+r_2)x+r_1r_2](https://tex.z-dn.net/?f=%28x-r_1%29%28x-r_2%29%3Dx%5E2-%28r_1%2Br_2%29x%2Br_1r_2)
So the trinomial
![x^2+kx-35](https://tex.z-dn.net/?f=x%5E2%2Bkx-35)
can be factored as long as
![\begin{cases}r_1+r_2=-k\\r_1r_2=-35\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dr_1%2Br_2%3D-k%5C%5Cr_1r_2%3D-35%5Cend%7Bcases%7D)
has integer solutions for
![r_1,r_2](https://tex.z-dn.net/?f=r_1%2Cr_2)
. Clearly, both have to be factors of -35, which leaves only a handful of cases:
![(r_1,r_2)=(1,-35)\implies r_1+r_2=-34](https://tex.z-dn.net/?f=%28r_1%2Cr_2%29%3D%281%2C-35%29%5Cimplies%20r_1%2Br_2%3D-34)
![(r_1,r_2)=(-1,35)\implies r_1+r_2=34](https://tex.z-dn.net/?f=%28r_1%2Cr_2%29%3D%28-1%2C35%29%5Cimplies%20r_1%2Br_2%3D34)
![(r_1,r_2)=(5,-7)\implies r_1+r_2=-2](https://tex.z-dn.net/?f=%28r_1%2Cr_2%29%3D%285%2C-7%29%5Cimplies%20r_1%2Br_2%3D-2)
![(r_1,r_2)=(-5,7)\implies r_1+r_2=2](https://tex.z-dn.net/?f=%28r_1%2Cr_2%29%3D%28-5%2C7%29%5Cimplies%20r_1%2Br_2%3D2)
So the possible values of
![k](https://tex.z-dn.net/?f=k)
are
![\pm34](https://tex.z-dn.net/?f=%5Cpm34)
and
![\pm2](https://tex.z-dn.net/?f=%5Cpm2)
.