Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:
2.08
Now, we estimate standard deviation:
s = 0.1564
For t-score, we need to determine degree of freedom and 
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
Answer:
$10t=m
Step-by-step explanation:
If for each hour is $10.
She would earn the number of hours times $10.
Example: She did babysitting for 4 hours this weekend. The equation is $10(4)=m or $10 x 4 = m. m=40
Answers B, C, D are all correct!
If a cheetah ran 196m is 8 seconds, then 196/8 = 24.5 meters per second.
Let’s verify all answers:
A) 24.5 x 6 = 147. 147m are ran in 6 seconds, not 125.
B) 24.5 x 10 = 245. This answer is correct!
C) We’ve establishes that a Cheetah ran 24.5 meters per second. Correct!
D) Since one minute equals 60 seconds, 24.5 x 60 = 1470. Correct!
E) 24.5 x 5 = 122.5. In this time frame, a cheetah wouldn’t run 125m.
Yintercepts are where x=0
set to zero to solve
0^2+4y^2=16
4y^2=16
divide 4
y^2=4
sqrt both sides
y=+/-2
xintercept is where y=0
x^2+4(0)^2=16
x^2+0=16
x^2=16
sdqrtboth sides
x=+/-4
yintercepts are (0,2) and (0,-2)
xintercepts are (4,0) and (-4,0)
