A rectangular pyramid has a rectangular base and 4 triangular faces.
First find the length of leg BC by using the Pythagorean theorem BC=132+52=12 ft if we find the midpoint of BC which is 6 ft we find where the angle bisector would touch the BC. From there we construct another triangle ANC where AC is equal to 5 ft and NC is equal to 6 ft where we can again use the Pythagorean theorem to find the length of the hypotenuse which is the angle bisector AN=Angle Bisector=62+52<span>=7.8102 ft.</span>
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Answer:
17
Step-by-step explanation:
all 4 numbers added up, 68, divide by the amount of numbers, which is 4, and you get the answer
Step-by-step explanation:
39500 x 103 = 4,068,500
in scientific notation, that ia 4.0685 x 10⁶
If we have 2 coordinates say: (x1,y1) and (x2,y2)
Then the formula for the midpoint is:
((x1+x2)/2,(y1+y2)/2)
And the formula for the distance is:
Sqrt((x2-x1)^2+(y2-y1)^2)
So here we have (-1,-4) and (-7,4)
The midpoint is:
((-1+-7)/2,(-4+4)/2) = (-8/2,0/2) = (-4,0)
The distance is:
Sqrt((-7- -1)^2+(4- -4)^2)
= sqrt((-6^2)+(8^2))
=sqrt(36+64)
=sqrt(100)
=10
