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3 years ago

Please help me with measurements

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

I dont know the answer but you may find this helpful:
-1 Quart = 1.13 British litres
-Fluid ounce = 0.028 Brtish litres
-1 gallon = 4.546 British litres
-1 Cup is 0.237 British litres

Now all the mesurments are the same i hope this helps a bit.

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PLEASE ANSWER! WHOEVER ANSWERS WILL BE MARKED AS BRAINLIEST AND GET 100 POINTS!

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Answer:

ok,i know

Step-by-step explanation:

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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

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Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 0.499, \sigma = 0.002$

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.504 - 0.494}{0.002}$

$Z = 2.5$

$Z = 2.5$ has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.496 - 0.494}{0.002}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

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4 years ago

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Each where used for 25 hours

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1. Draw an appropriate Venn diagram to depict each of the following sets. U = The set of integers. A = The set of even integers.

CaHeK987 [17]

The attached diagram represents the Venn diagram of the sets

<h3>How to draw the Venn diagram?</h3>

The sets are given as:

The universal set, U = The set of integers.
A = The set of even integers.
B = The set of odd integers.
C = The set of multiples of 3.
D= The set of prime numbers

From the above representation, we have the following highlights:

Set A and set B will not intersect, because no number can be even and odd
Set C and set D will intersect set A because they have common elements 6 and 2, respectively
Set C and set D will intersect set B because they have common elements 3 and 3, respectively

Using the above highlights, we can now draw the Venn diagram

See attachment for the Venn diagram