Answer:
mini disc diameter:disc diameter
14cm:21cm = 7:10.5 = 3.5:5.25 = 1:1.5
Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase in the length of the shadow
We have by sin rule;
90/(sin (22°) = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°) = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore;
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.
I used the completing the square method to get the (x+2)^2. The final line is in standard form.
Answer:
0.0707 cm
Step-by-step explanation:
We can solve this using pythgaoras theorem:
a² + a² = c² (We can use the same letter, a, because the lengths are the same length; a² + a² = 2a²)
2a² = 0.1² (simplify the right side; 0.1 × 0.1 = 0.01)
2a² = 0.01 (0.01 ÷ 2 = 0.005)
a² = 0.005 (square root both sides)
a = 0.070710... ≈ 0.0707 cm
Hope this helps!