Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
1 answer:
Answer:
392
Step-by-step explanation:
Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.
Extend lines XQ, YR, YS and XP and mark their intersection as A and B.
Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore
- all angles of the quadrilateral XAYB are right angles
- all sides of XAYB are congruent and equal to 6 + 8 = 14 units.
Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,
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