2 years ago

Based on the slopes, what can you say about the relationship between DE and BC?

Mathematics

1 answer:

solong [7]2 years ago

6 0

Answer:

DE and B⁢C are parallel line segments.

Step-by-step explanation:

Edmentum-

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Antiderivative F(x)

This is the integral of $F^{\prime}(x)$

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

$F(x) = \int (6 + 24x^3 + 18x^5) dx$

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$F(x) = 6x + 6x^4 + 3x^6 + K$

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$F(X) = 0$ when $x = 1$ . We use this to find K.

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$K = -15$

Thus

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Based on the slopes, what can you say about the relationship between DE and BC?​

Based on the slopes, what can you say about the relationship between DE and BC?