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Temka [501]
3 years ago
8

Based on the slopes, what can you say about the relationship between DE and BC?​

Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

DE and B⁢C are parallel line segments.

Step-by-step explanation:

Edmentum-

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−10 = −0.4k<br><br> this is probably easy but can someone find k
azamat

Answer: k = 25

hope this helped :)

5 0
2 years ago
The graph of g(x) is a reflection and translation of ∛x see attachment, please help
svetoff [14.1K]
<h2>Hello!</h2>

The answer is: g(x)=-\sqrt[3]{x-1}

<h2>Why?</h2>

Let's check the roots and the shown point in the graphic (2,-1)

First,

0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1

then,

g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1

So,  we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

(g(x)=-\sqrt[3]{x-1})

Second,

Evaluating the function at (2,-1)

y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1

-1=-1

It means that the function passes through the given point.

Hence,

The equation which represents g(x) is g(x)=-\sqrt[3]{x-1}

Have a nice day!

5 0
3 years ago
Please help asap &lt;3
sladkih [1.3K]

Answer:

think it's A (0,6) if not then idk maybe D

6 0
3 years ago
Read 2 more answers
I neee help Please!!!
marishachu [46]
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6 0
3 years ago
Find sin theta if cos theta is 4/5
Dima020 [189]

Answer:

Step-by-step explanation:

hello :

cos²θ +sin²θ = 1 and cosθ =4/5

(4/5)² + sin²θ = 1 so : sin²θ = 1 - 16/25

sin²θ = 9/25 = (3/5)²

sinθ = 3/5 or sinθ = - 3/5 because : (3/5)²= (- 3/5)²= 9/25

5 0
3 years ago
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