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Umnica [9.8K]
3 years ago
15

How many equal sections divide a directed line segment if it is to be partitiioned with a 7:10 ratio?

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0
Im Not Sure But Im Thinking 7/10 Wrote As in A Fraction . 


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5. Which side lengths could not form a triangle?
romanna [79]

Answer:

A, B, C, D

Step-by-step explanation:

A is equal to 54, B is equal to 23, C is equal to 72, and D is equal to 84.

6 0
2 years ago
Read 2 more answers
Find the area to this figure
12345 [234]

I think the answer is 62 cm2

7 0
3 years ago
Mr.lucido purchases a new video game system that is on sale for 35% off the regular retail price. if the retail price is $429, w
sammy [17]

Answer:

Regular price: $429

35% discount: 278.85

5% tax: $13.94

Final cost: 292.79

Step-by-step explanation:

regular price=$429

0.35(429)=150.15

429-150.15=278.85

35% discount amount: $278.85

278.85(0.05)=13.94

278.85+13.94=292.79

6 0
2 years ago
Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.
Oksanka [162]

Answer:

Option (1)

Step-by-step explanation:

x               -2              -1                 0                    1                   2

y               10            2.5                0                  2.5                3.0

Ist difference,

d_1=y_2-y_1

    =2.5-10=-7.5

d_2=y_3-y_2

    =0-2.5

    = -2.5

d_3=y_4-y_3

    =2.5-0

    = 2.5

d_4=y_5-y_4

    =10.0-2.5

    = 7.5

2nd difference,

x_1=d_2-d_1

    =-2.5+7.5

    = 5

x_2=d_3-d_2

    =2.5+2.5

    = 5

x_3=d_4-d_3

    =7.5-2.5

    = 5

Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

2.5 = a(1)² + b(1)

a + b = 2.5 ------(2)

By adding equations (1) and (2),

2a = 5

a = 2.5

and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

8 0
3 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
11 months ago
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