A debt greater than 20$ and less than 30$

Mathematics

1 answer:

Vsevolod [243]3 years ago

5 0

Answer:

A debt greater than 20$ and less than 30$ is 25$

Step-by-step explanation:

A brainliest would be nice please :D

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A right circular cylinder has a diameter of 16 mm and a height of 12 mm. what is the volume of the cylinder in terms of π?

valina [46]

Volume of the cylinder = hr²π

diameter = 2 × radius
16 = 2 × r
r = 16/2
r = 8 mm

V = hr²π
V = 12 × 8² × π
V = 12 × 64 × π
V = 768π mm³

8 0

3 years ago

Read 2 more answers

A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the

Lostsunrise [7]

Answer: $5.7\ cm$

Step-by-step explanation:

Given

Rectangle has an area of $19.38\ cm^2$

Suppose rectangle length and width are $l$ and $w$

If each side is increased by $1.50\ cm$

Area becomes $A_2=35.28\ cm^2$

We can write

$\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)$

Substitute the value of width from (ii) in equation (i)

$\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7$