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3 years ago

A debt greater than 20$ and less than 30$

Mathematics

1 answer:

Vsevolod [243]3 years ago

5 0

Answer:

A debt greater than 20$ and less than 30$ is 25$

Step-by-step explanation:

A brainliest would be nice please :D

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−39 = −0.6k<br> what does k equal

denis-greek [22]

Answer: k=65

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

Gnoma [55]

The converted fractions are 3/12 and 5/12 and the sum is 2/3

<h3>How to convert the fractions?</h3>

From the question, the fractions are given as

1/4 and 5/12

The denominators of these fractions are

4 and 12

So. we start by calculating the LCD of the denominators

So, we have

4 = 2* 2

12 = 2 * 2 * 3

This gives

LCD = 2 * 2 * 3

Evaluate

LCD = 12

This means that the common denominator must be 12

So, we have

1/4 and 5/12

Multiply 1/4 by 3/3

This gives

3/12 and 5/12

When the fractions are added, we have

3/12 + 5/12 = (3 + 5)/12

Evaluate

3/12 + 5/12 = 8/12

Reduce fraction

3/12 + 5/12 = 2/3

Hence, the sum of the fractions is 2/3

Read more about fractions at

brainly.com/question/1622425

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8 0

1 year ago

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0

3 years ago

You have two job offers. Conn’s offers a weekly salary of $500 plus commission of 3% of sales. Best Buy offers a weekly salary o

denis23 [38]

Answer: y=3x+500 and y=2x+400

Step-by-step explanation:

you are going to get the weekly salary anyways, but the percentage of sales all depends on what you are doing to make sure you are selling things.

7 0

2 years ago

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$

Step-by-step explanation:

6 0

3 years ago