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hram777 [196]
3 years ago
14

FCD=x+41, BCF=x+78, BCD=95. Find x

Mathematics
1 answer:
Lorico [155]3 years ago
5 0
You'll set the two expressions equal to 95.
So 2x+119=95
Then 2x=-24
Finally x=-12
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When driving at night, you should dim your headlights when:
Tatiana [17]

Answer:

Meeting or following another vehicle

Step-by-step explanation:

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2 years ago
-3y-2=7 what is the value of y
tiny-mole [99]

Answer:

y = -3

Step-by-step explanation:

Add 2 to each side to isolate the -3y. Doing this leaves you with -3y=9. You then divide each side leaving you with y = -3

6 0
2 years ago
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Help me please !!!<br> Need asap!
marusya05 [52]
Area of the triangle =[6 x (6√3) /2 ] / 2 ===>9√3=15.588

Area of each sector : (π/6). r² = π/6 x  9===.>4.712
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The shaded area is

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8 0
3 years ago
Colin drove 45 minutes to the air port. He arrived 90 minutes before his flight departed and then he spent 70 minutes in the air
Gnom [1K]

Given: The time taken to do each activity from Colin's house to his hotel in given.

  • he drove to the airport for 45 minutes
  • he waited at the airport for the flight to depart for 90 minutes
  • his fight duration was 70 minutes
  • upon landing, he gathered his luggage for 20 minutes
  • he drove to the hotel for 35 minutes

To Find: what is true of any expression that represents the total time Collin spent traveling from his house to the hotel

Solution: Any expression will involve the sum of all the durations of his various activities i.e., 260 minutes or 4 hours and 20 minutes.

Explanation:

As each of the activities described is an independent activity that does not overlap, we can easily sum up the durations of each to find the total time Collin took from his house to the hotel.

We add it as follows :

he drove to the airport for 45 minutes + he waited at the airport for the flight to depart for 90 minutes + his fight duration was 70 minutes + upon landing, he gathered his luggage for 20 minutes + he drove to the hotel for 35 minutes.

So, 45+90+70+20+35 = 260 minutes

which means it took a total of 260 minutes or 4 hours and 20 minutes from Collin's house to his hotel.

7 0
3 years ago
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The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students
bija089 [108]

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

\mu=84

a standard deviation of 5

so,

\sigma=5

we have

x=89

now, we can use z-score formula

z=\frac{x-\mu}{\sigma}

now, we can plug values

z=\frac{89-84}{5}

z=1

now, we can use calculator

and we get

p(z>1)=0.1587

So,

The percentage of the students scored higher than 89% is 15.87%

5 0
3 years ago
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