1 dime is required to make $1.02 cents using 9 coins collections
<h3>How to solve</h3>
<u>Given data</u>
9 coins
a collection of pennies, nickels, dimes, and quarters
total of $1.02 with at least one coin of each type
solution
$1.02 = 102cents
1 penny = 1 cent
1 nickel = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
having one coin of each means 4 coins which is equal to:
1 + 5 + 10 + 25 = 41 cents (fulfilling the first condition remaining 5 coins)
102 - 41 = 61
balancing the remaining coins to make up 61, we first get a penny to reduce the amount 60 cents ( 4 coins remaining )
hence we have
2*25 +2*5 = 60 cents ( 2quarters 2 nickel)
in total we have
2 pennies + 3 nickels + 1 dime + 3 quarters = 9 coins
2 * 1 + 3 * 5 + 1 * 10 + 3 * 25 = 102 cents
Therefore 1 dime is required to make $1.02 cents using 9 coins collections
Read more on dimes here: brainly.com/question/435257
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Answer:
<h2>Any real number that cannot be expressed as a ratio of two integers.</h2>
Step-by-step explanation:
OPTIONS R NOT HERE
HOPE IT HELP
<span>Mica should have added 2 to 3 instead of 1 to 3.
She factored out a 2 on the righthand side, so adding 1 within the parentheses is equivalent to adding 2 outside the parentheses. Since this is an equation, what we do to one side, we must do to the other, so Mica should've added 2 to the lefthand side.</span>
3 in the first question 4 on the last question!!!
Answer:
Formular for coordinate length:
In considerance of coordinates given of A and B
therefore substitute:
