Explain why these answers are true.
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The margin of error for a sample proportion is given by
where:
is the z score associated with the confidence level, p is the sample prortion and n is the sample size.
We assume a confidence level of 95%, then
p = 52% = 0.52 and n = 2251
Therefore, margin of error =
The the interval that is likely to contain the true population proportion is between 49.9% and 54.1%.
where:
We assume a confidence level of 95%, then
p = 52% = 0.52 and n = 2251
Therefore, margin of error =
The the interval that is likely to contain the true population proportion is between 49.9% and 54.1%.