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pychu [463]
2 years ago
13

(b) Express the number 17 (i) in base 2 (ii) in base 5

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
5 0

Answer:

Step-by-step explanation:

IF 17 is in base 10

THEN

17₁₀ = 1 x 10¹ + 7 x 10⁰

10001₂ = 1 x 2⁴ + 0 x 2³ + 0 x 2² + 0 x 2¹ + 1 x 2⁰

32₅ = 3 x 5¹ + 2 x 5⁰

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Best explained and correct answer gets brainliest.
topjm [15]
U = (-2,3)

V = (3,0)

midpoint of UV

= ( (3-2)/2 , (3+0)/2 )

= ( 1/2 , 3/2)

= ( 0.5 , 1.5)

X = (0.5 , 1.5) [from fig]

midpoint of UV = X

W= (-2,-3)

V =( 3.0)

Y = ( (-2+3)/2 , (-3+0)/2 )

= (0.5 , - 1.5)

Y = ( 0.5 , -1.5) [ from fig ]

Y is the midpoint of WV

by midpoint theorem ,

UW = 2( XY )
6 0
2 years ago
a six sided die is rolled 15 times with these results (1,1) (2,3) (3,4) (4,4) (5,1) (6,2) what is the experimental probabilitly
GenaCL600 [577]

Answer:

seems to easy to be true but the answer is 7/12 cause it's a fraction and it can't be simplified

5 0
2 years ago
A tree that is 4 ft tall is growing at a rate of 1 ft each year a tree that is 12 feet tall is growing at a rate of 1/2 ft each
Andreyy89

Answer:

16 years

Step-by-step explanation:

Given data

For the first tree

let the expression for the height be

y=4+x--------------1

where y= the total height

          4= the initial height

          x= the number of years

For the second tree, the expression is

y=12+0.5x-------------2

Equate 1 and 2

4+x=12+0.5x

x-0.5x=12-4

0.5x= 8

x= 8/0.5

x=16

Hence it will take 16 years for both trees to have the same height

5 0
2 years ago
What is the leading coefficient of the function f(x)= 3x^5+6x^4-x-3
Natali5045456 [20]

3. The leading coefficient of the function f(x)= 3x⁵+6x⁴-x-3 is 3.

For the function  f(x)= 3x⁵+6x⁴-x-3 , the highest power of x is 5, so the degree is 5. The leading term is the term containing that degree, 3x⁵. The leading coefficient is the coefficient of that term, 3.

4 0
3 years ago
Help! Please!
Elan Coil [88]
Because there are infinitely many numbers that are either greater or less than variable x.
5 0
3 years ago
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