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Mariana [72]
3 years ago
14

AAAAAAAAAAAAAASSSSSSSSSSAAAAPPPPPPPPP.........

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0
The y-intercept is the base pay.
Choice A).
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Substitute 9 into each equation to determine if 9 is the solution. Drag each equation into the correct column.
IRISSAK [1]

Answer:

m times 3 = 27

b plus 4 = 13

p minus 5 = 4

Those can all be solved with 9

the other can not

Step-by-step explanation:

i hope this helped

4 0
3 years ago
4t + 2u2 - u3 ; t=2 u=1
melisa1 [442]
9, I believe.
4(2)+2(1)^2-(1)^3 (^ just means to the power of "exponent")
8+2-1=9
3 0
4 years ago
Remy has $14,000 to invest in two mutual funds. One fund pays interest at 4% per year and the other fund pays interest at 7% per
AnnyKZ [126]
$4,200 at 4%, $9,800 at 7%
5 0
3 years ago
PLEASE HELP ME WITH THIS!! ;(
DochEvi [55]

Answer:

Zoom in and mark me as brainliest

4 0
3 years ago
A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how
love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

  • There are 26 letters in the alphabet
  • We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

26*25*24*23*10*9 = 32,292,000

When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
8 0
3 years ago
Read 2 more answers
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