Step-by-step explanation:
The dividend is the number which is being divided and the divisor is what you divided by. An example is:
12 ÷ 3. The quotient is 4.
Answer:
2np + p²
Step-by-step explanation:
The general formula for the area of a square is A = s², where s = the length of one side of the square. In the case of the smaller square the area would be: n x n = n². Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'. To find the area of the larger square, we have to take the length x length or (n +p)².
Using FOIL (forward, outside, inside, last):
(n + p)(n+p) = n² + 2np + p²
Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.
n² + 2np + p² - n² = 2np + p²
Answer:
<em>x = 7</em>
Step-by-step explanation:
Simplifying
17 = 3X + -4
Reorder the terms:
17 = -4 + 3X
Solving
17 = -4 + 3X
Solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '-3X' to each side of the equation.
17 + -3X = -4 + 3X + -3X
Combine like terms: 3X + -3X = 0
17 + -3X = -4 + 0
17 + -3X = -4
Add '-17' to each side of the equation.
17 + -17 + -3X = -4 + -17
Combine like terms: 17 + -17 = 0
0 + -3X = -4 + -17
-3X = -4 + -17
Combine like terms: -4 + -17 = -21
-3X = -21
Divide each side by '-3'.
X = 7
Simplifying
X = 7
12 cm:102 ft
-------- ------
12 12
1 cm:8.5 ft
The scale is 1 cm equals 8.5 ft.
Answer:

Step-by-step explanation:

This is a homogeneous linear equation. So, assume a solution will be proportional to:

Now, substitute
into the differential equation:

Using the characteristic equation:

Factor out 

Where:

Therefore the zeros must come from the polynomial:

Solving for
:

These roots give the next solutions:

Where
and
are arbitrary constants. Now, the general solution is the sum of the previous solutions:

Using Euler's identity:


Redefine:

Since these are arbitrary constants

Now, let's find its derivative in order to find
and 

Evaluating
:

Evaluating
:

Finally, the solution is given by:
