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lawyer [7]
3 years ago
6

Anyone want my username?

Mathematics
1 answer:
romanna [79]3 years ago
7 0
Lol that’s poggers dude
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Write a division problem with as the dividend and 3 as the divisor. Then, find the quotient.
Mekhanik [1.2K]

Step-by-step explanation:

The dividend is the number which is being divided and the divisor is what you divided by. An example is:

12 ÷ 3. The quotient is 4.

4 0
3 years ago
Read 2 more answers
Each side of the smaller square in the figure below is n inches long, and each side of the larger square is p inches longer than
lana66690 [7]

Answer:

2np + p²

Step-by-step explanation:

The general formula for the area of a square is A = s², where s = the length of one side of the square.  In the case of the smaller square the area would be: n x n = n².  Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'.  To find the area of the larger square, we have to take the length x length or (n +p)².

Using FOIL (forward, outside, inside, last):

(n + p)(n+p) = n² + 2np + p²

Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.

n² + 2np + p² - n² = 2np + p²


8 0
3 years ago
What is the solution of the equation 17 = 3x − 4?
pogonyaev

Answer:

<em>x = 7</em>

Step-by-step explanation:

Simplifying

17 = 3X + -4

Reorder the terms:

17 = -4 + 3X

Solving

17 = -4 + 3X

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3X' to each side of the equation.

17 + -3X = -4 + 3X + -3X

Combine like terms: 3X + -3X = 0

17 + -3X = -4 + 0

17 + -3X = -4

Add '-17' to each side of the equation.

17 + -17 + -3X = -4 + -17

Combine like terms: 17 + -17 = 0

0 + -3X = -4 + -17

-3X = -4 + -17

Combine like terms: -4 + -17 = -21

-3X = -21

Divide each side by '-3'.

X = 7

Simplifying

X = 7

3 0
3 years ago
Read 2 more answers
A model length of 12 cm. represents an actual length of 102 ft. What is the scale for the model?
Rom4ik [11]
12 cm:102 ft
--------  ------
12        12
1 cm:8.5 ft

The scale is 1 cm equals 8.5 ft.
5 0
3 years ago
Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

5 0
3 years ago
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