Question

Equation of a line perpendicular to y=-11x-4 going through (3,3)

Answer 1

Answer: y = $\frac{x}{11}$ + 30/11

Step-by-step explanation:

Two line are said to be perpendicular to each other if the slope of the first line = -1 / the slope of the second line , that is

If the slope of the first line is M1 and the slope of the second line is M2 , then M1 = -1 / M2.

From the equation given , M1 = - 11 , that means M2 = 1 / 11

Using the formula  y - y1 = m ( x - x1) to calculate the equation , we have

y - 3 = 1/11 ( x - 3)

Multiply through by 11 , we have

11 ( y - 3 ) = x - 3

11y - 33 = x - 3

11y = x + 30

y = x/11 + 30/11