There is 6 regular packs and 6 value packs so add those (6+6=12). Divide 12 by 2 (because there's 2 socks in a pair) and get 6. Then divide 402 by 6 and get 67 pairs. Do the same for the second location.
Answer: The range of the tree heights at yard work is greater than the range of the tree heights at the grow station
Step-by-step explanation:
yard works: 7,9,7,12,15
The grow station:9,11,6,12,7
mean of yard works = 7+9+7+12+15/5
=50/5=10
mean of grow station=
9+11+6+12+7 /5
=45/5 =9
The mean of tree heights at yard work is greater than that of grow station.
median(tree at yard work):7,7,9,12,15
median=9
median(tree at grow station)=6,7,9,11,12
median=9
The median of the tree height at yard work is equal to the median of that of tree station.
Range(yard work) = 15 - 7 =8
Range (tree station) =12-6=6
The range of the tree heights at yard work is greater to the tree heights at that of tree station
A quadratic equation is an equation whose leading coefficient is of the second degree. The factored form of the quadratic equation x²-x-2 is (x+1)(x-2).
<h3>What is a quadratic equation?</h3>
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.
It is written in the form of ax²+bx+c.
The factored form of the quadratic equation can be done in the following manner,
Thus, the factored form of the quadratic equation x²-x-2 is (x+1)(x-2).
Learn more about Quadratic Equations:
brainly.com/question/2263981
Answer:
r = √13
Step-by-step explanation:
Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms: x^2 + 6x + y^2 -2y = 3. Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."
We need to "complete the square" of x^2 + 6x. I'll just jump in and do it: Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x: x^2 + 6x + 3^2 - 3^2. Then do the same for y^2 - 2y: y^2 - 2y + 1^2 - 1^2.
Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2. Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1. Making these replacements:
(x + 3)^2 - 9 + (y - 1)^2 -1 = 3. Move the constants -9 and -1 to the other side of the equation: (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13
Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r: r^2 = 13, so that the radius is r = √13.
