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kupik [55]
3 years ago
15

The times for three runners in a 100 yard dash are 9.85 s, 9.6 s and 9.625 s. What is the winning time?

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

9.6 is first

Step-by-step explanation:

9.6 , 9.625, then 9.85 is the order finished the race, the larger the time (number)  the later they crossed the finish line

Hope this helps : )

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Please help me out!​
seropon [69]

Answer:

Second option

Third option

Fourth option

Step-by-step explanation:

We have the following quadratic function

f(x) =(x-1)(x+7)

Use the distributive property to multiply the expression

f(x) =x^2+7x-x-7

f(x) =x^2+6x-7

For a function of the form f (x) = ax ^ 2 + bx + c the x coordinate of the vertex is:

x =-\frac{b}{2a}

Then in this case the coordinate of the vertex is:

x =-\frac{6}{2(1)}

x =-3

To obtain the y coordinate of the vertex we evaluate the function at x = -3

f(-3) =(-3)^2+6(-3)-7

f(-3) =9-18-7

f(-3) =-16

Then the vertex is:  (-3, -16)

We can see in the graph that the zeros of the function are x=1 and x=-7

Then the function is decreasing from -∞ to -3 and then it is increasing from -3 to ∞

The function is positive for x and x> 1

The correct answers are:

Second option

Third option

Fourth option

7 0
3 years ago
Solve the equation below
Agata [3.3K]
Set up the equation:

4(8.75x-2)=97
35x-8 =97
35x =97+8
35x =105
x. =3

The value of x is 3.
7 0
3 years ago
A recipe calls for of a cup of milk for 11 cookies. How many cups of milk are needed to make 66 cookies?
stiv31 [10]
It should be 7 cups of milk
5 0
3 years ago
the vertices of triangle PQR are P(-3, 8), Q(-6, -4), and R(1, 1). If you reflect triangle PQR across the x-axis, what will be t
otez555 [7]

Answer:

The coordinates of the vertices of the image will be:

P'=(-3,-8)

Q'=(-6,4)

R'=(1,-1)

Step-by-step explanation:

If you reflect a point P=(x,y) across the x-axis, the coordinates of the image will be P'=(x,-y), then:

P=(-3,8)=(xp,yp)→xp=-3, yp=8→P'=(xp,-yp)→P'=(-3,-8)

Q=(-6,-4)=(xq,yq)→xq=-6, yq=-4→Q'=(xq,-yq)=(-6,-(-4))→Q'=(-6,4)

R=(1,1)=(xr,yr)→xr=1, yr=1→R'=(xr,-yr)→R'=(1,-1)

3 0
4 years ago
Find the equation of the line that passes thru (-1,-5) and is parallel to 3x+y=-5. Show work.
sertanlavr [38]

Answer:

y=-3x-8

Step-by-step explanation:

slope-intercept form:

y=mx+b

Start with the given equation, and to find the slope, convert it to slope-intercept form by solving for y.

3x+y=-5

In this case, all you need to do is subtract 3x from both sides.

y=-3x-5

Here, the slope is -3. The slope of a parallel line will also be -3.

Now, we have 3 known variables. We have the slope and the x and y of a known point. Use those 3 knowns to solve for the 1 unknown, the y-intercept.

y=mx+b\\-5=(-3)(-1)+b\\-5=3+b\\-8=b\\b=-8

Finally, with the slope and the y-intercept, you can write the equation of the line:

y=-3x-8

3 0
3 years ago
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