Please dont put question mark on these they dont make sense so make thi sbetter!
Please!
Answer:
<u>Oliver and Lenny reached the top of the hill at the same time</u>
<u>The proportion of time Oliver spent hiking to that of Lenny is 1:1</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Oliver's speed = 5 km/h during the first half, then decreased his speed to 4 km/h during the second half.
Lenny's speed = 4 km/h during the first half, then increased his speed to 5 km/h in the second half.
2. Who reached the top of the hill first? What is the proportion of time he spent hiking to that of his friend?
Let's assume the distance from the bottom to the top of the hill is 10 kilometers for calculating the time it will take Oliver and Lenny to reach the top of the hill:
Speed = Distance/Time
Time = Distance/Speed
Oliver = Time of hiking first 5 km + Time of hiking second 5 km
Lenny = Time of hiking first 5 km + Time of hiking second 5 km
Oliver = 5/5 + 5/4
Oliver = 1 + 5/4 = 2 1/4 hours
Lenny = 5/4 + 5/5
Lenny = 5/4 + 1 = 2 1/4 hours
<u>Oliver and Lenny reached the top of the hill at the same time</u>
<u>The proportion of time Oliver spent hiking to that of Lenny is 1:1</u>
The width and height of the tv as well as the length and width of the back of your car
Answer:
LP = 16 units (8 + 8)
x = 4.25 units
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
Mixed candy question... Skittles jar... to be filled with Jelly beans.
Let's first calculate the volume of the jar. We'll assume it's a regular cylindrical prism jar, unlike the one on the photo which is narrower on top.
V = π * r² * h = π * (3.5)² * 11.5 = 140.875 π = 442.6 cubic cm
Now, we don't have the precise measurement of a jelly bean, but we know it's roughly 2-3 cubic cm. The precision isn't needed to answer this question, just to have a rough idea... it's no 300 cu cm per jelly bean.
So, let's assume a 3 cu cm per jelly bean (2 cu cm wouldn't the final answer)....
442.6 / 3 = 147.5 jelly beans, approximately.
So, can they fit 100,000? No
Can we fit 10,000 in there? No
Can we fit 100? Yes.
Can we fit 1? Certainly
The most reasonable lower-limit would then be 100.
