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3 years ago

What is the area of the figure? Round to the nearest tenth.

Mathematics

2 answers:

diamong [38]3 years ago

5 0

Answer:

14.0 cm its a

Step-by-step explanation:

Scrat [10]3 years ago

5 0

The answer to this would be A

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A train leaves at 11.15 and arrives at its destination at 12.23. If the train travelled 95 km, what was it's average speed in km

xxMikexx [17]

Answer:

Average speed v = 83.8 km/h

Step-by-step explanation:

Given;

Distance travelled = 95 km

Time taken t = 12.23 - 11.15 = 1 hour 8 minutes

t = 1 + 8/60 hours = 1.133 hours.

Average speed v = distance travelled/time taken

substituting the values;

v = 95 km ÷ 1.133 hours

Average speed v = 83.8 km/h

4 0

3 years ago

Im doing decimals greatest to least and i need help with number 12 and 13

erma4kov [3.2K]

(I know there isnt any real problem here to solve, but heres a tip on how to solve greatest to least with decimal problems)

1. Just because a number looks big, doesn't mean it is big

Example: 1.00000000000001 < 1.1

just look at the numbers ^ and dont just hastily read it over assuming that 1.1 is smaller because it "has less digits"

2. Negative numbers are... opposite. and they are less than positive numbers

-3.4 > -4.1

Why is this? Well, if you look on a line, with the point 0 in the middle, you can see that -3.4 is not as far away from 0 as -4.1 is. So the idea is to apply opposite logic for negative numbers

I hope these tips helped!! :D

3 0

3 years ago

Read 2 more answers

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

6 0

3 years ago

Read 2 more answers

Estimate. Round to the greatest place value. Circle whether the estimate is greater then or less then the actual product.

nataly862011 [7]

Answer:

The estimate is greater then.

Step-by-step explanation:

143*2=286

286*2=572 not 6,517

4 0

3 years ago

I really need help with this problem please help

VLD [36.1K]

I think the answer is going to be a

7 0

3 years ago