All categories

3 years ago

How many subsets of 1,2,3,4,6,8,10,15 are there for which the sum of the elements is 15

Mathematics

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

10+5

10+1+4

10+3+2

8+1+2+4

8+6+1

6+4+3+2

You might be interested in

Please help. thank you :)

Zina [86]

Answer:A

Step-by-step explanation: your answer is A

5 0

3 years ago

Martin has 128 pencils that he is putting

rosijanka [135]

128 pencils divided by 6 pencils that can be put in a box; 128÷6=21 with a remainder of 3

Martin needs 3 more pencils for the last box, beacuse he has 3 leftovers and 6 can go into the box. 6-3=3

4 0

3 years ago

I need help with this asappp

Rus_ich [418]

The answer would be 45. Thank you very much and good luck on there!

6 0

3 years ago

Read 2 more answers

Find the product. Write your answer in scientific notation. (3 x 10^2)×(4×10^5)

suter [353]

Answer:

12 * 10 ^ 7

Step-by-step explanation:

3 * 10 ^ 2 * 4 * 10 ^5

= 12 * 10^ 2 + 5

= 12 * 10 ^ 7

Hope it will help :)

7 0

2 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0

3 years ago