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4 years ago

Which symbol correctly compares these fractions? 13 20 ___ 7 10

2 answers:

fomenos4 years ago

7 0

These are fractions? Like 13/20 and 7/10? Is so the symbol would be 13/20 < 7/10 because 7/10 is a higher fraction than 13/20

Leona [35]4 years ago

7 0

Answer:

$\frac{13}{20} < \frac{7}{10}$

Step-by-step explanation:

$\frac{13}{20} \ and \ \frac{7}{10}$

Now we compare both the fractions

To compare both the fractions, we make the denominators same

LCD is 20

To make the denominators same we multiply the denominator of second fraction by 2

$\frac{7 \cdot 2}{10 \cdot 2}$

$\frac{14}{20}$

$\frac{13}{20}$ and $\frac{14}{20}$

13/20 is smaller than 14/20

$\frac{13}{20} < \frac{14}{20}$

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

3 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0

4 years ago

Which of the x-values are solutions to both of the following inequalities? 60 > X and x > 57. Also, Please hurry I will gi

PolarNik [594]

Answer:

Step-by-step explanation:

x must be a number between 60 and 57 and those numbers are 58 or 59

60 is greater than 59, and 59 is greater than 57

5 0

3 years ago

Read 2 more answers

Write an equation for the hyperbola with vertices (-7,0) and (7,0), conjugate axis of length of 10?

lina2011 [118]

The hyperbola is more or less as in the picture below

notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component

the conjugate axis is 10, notice the length of the "b" component

thus $\bf \textit{hyperbola with horizontal traverse axis }\\\\
\cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})$

so, hmmmm plug in those values

6 0

3 years ago

How many pounds are 49 kg? And what about 50 kg? I need exact answers. Thnxs?

12345 [234]

1 kg = 2.20462 lbs....so 49 kg = (49 * 2.20462) = 108.02638 lbs
and 50 kg = (50 * 2.20462) = 110.231 lbs

6 0

3 years ago