A = bh/2
A = 6 . 3 / 2
A = 18/2
A = 9
The solution to the problem is:
4 < t < 5
Given that the height of the ball is given by the equation:
h(t) = 16t² + 144t + 5
h represents the height and t represent the time taken to achieve the height.
To determine the time interval for the height to be greater than 325 feet, we need to equate h(t) to 325, hence:
-16t² + 144t + 5 > 325
-16t² + 144t - 320 > 0
-t² + 9t - 20 > 0
-t² + 4t + 5t - 20 > 0
-t(t - 4) + 5(t - 4) > 0
(t - 4)(-t + 5) > 0
t - 4 > 0; -t + 5 > 0
t > 4, t < 5
Therefore the interval for the height greater than 325 ft is:
4 < t < 5
Find more at: brainly.com/question/17718371
The correct anwer is C I think... I hope That helps :)
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Answer: 
Step-by-step explanation:
