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Anarel [89]
3 years ago
12

35 POINTS Read the excerpt from "Pakistan's Malala."

English
2 answers:
Lena [83]3 years ago
7 0

Answer:

the first thing so many people in your notebook is a 3

zavuch27 [327]3 years ago
5 0

Answer:

"On the blog, she praised her father, who was operating one of the few schools...."

Explanation:

That is what happened in the story.

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Imagine that you have chosen to memorize and recite Shakespeare's "Sonnet 18." What is the first step you should take once you h
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Answer:

The first step to be taken when trying to memorize a poem is to read the poem aloud.

Explanation:

By reading a poem aloud constantly, the individual discovers what the poem is about, the sound of the words, and find the meanings of the words not understood and also find out the rhyming of the words. By reading aloud constantly, the individual is able to memorize the poem.

Therefore, in order to memorize 'sonnet 18" by Shakespeare, The first step to take is for one to always read the poem aloud and be relentless as well as patient. One can also write out the poem or decide to act the lines by engaging all the senses.

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3 years ago
Which lines from Mark Antony's speech in Julius Caesar use logos?
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<span>C. My heart is in the coffin there with Caesar, / And I must pause till it come back to me.</span>
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4 years ago
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3 0
3 years ago
Stainless steel rod has a gap of 0.0371 mm between its end and a rigid wall. The modulus of elasticity E = 210 GPa. The coeffici
alexgriva [62]

Answer:

The value of stress in the rod is 220.9 MPa

Explanation:

As the data is not complete, a similar question is found online and the missing data is used from that question. Similar question is attached herewith.

From the given data

The allowed total strain is given as \delta_a=0.0371 mm

The length of the rod is missing in this data which in the additional data is l=290 mm

The Modulus of Elasticity is given as E=210 GPa

The coefficient of thermal expansion is given as α= 10 ×10⁻⁶ mm / mm⋅°C.

The initial temperature is room temperature which is given as T1=22C

The final temperature is given as T2=140 C

The strain due to stress is given as

\delta_s=\dfrac{\sigma l}{E}

\delta_s=\dfrac{\sigma (0.290)}{210\times 10^9}\\\delta_s=1.38095\sigma \times 10^{-12}

Now the thermal strain is given as

\delta_c=l\alpha \Delta T\\\delta_c=0.290\times 10 \times 10^{-6}(T_2-T_1)\\\delta_c=0.290\times 10 \times 10^{-6}(140-22)\\\delta_c=0.0003422

So now the equation of the allowed strain is given as

\delta_a=\delta_s+\delta_c\\0.0371\times 10^{-3}=1.38095\sigma \times 10^{-12}+0.0003422\\\dfrac{1.38095}{10^{12}}\sigma+0.0003422=\frac{0.0371}{1000}\\\sigma=-\dfrac{10^{12}\times \:0.0003051}{1.38095}\\\sigma=-220934863.68 Pa\\\sigma=-220.9 MPa

The negative sign indicate that the stress is compressive.

The value of stress in the rod is 220.9 MPa

8 0
3 years ago
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