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3 years ago

Someone help me ASAP pleasssse

Mathematics

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

A) I

Step-by-step explanation:

C is in 4th vertex and if moved 4 units it wii be in 1st vertex.

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A tournament is being run between two teams, A and B. This is a 2- tournament meaning that the first team to win 2 games is the

natta225 [31]

Answer:

Step-by-step explanation:

For first game PA = 1/3

For second game PA = 1/3 ( If A is not lost in first game )

= 2/5 (If A is lost in first game )

For conclusion of game in three matches :

If A wins , the probability is

PA , PB , PA = 1/3 X 2/3 X 3/5 = 6/45

PB , PA , PA = 2/3 X 3/5 X 1/3 = 6/45

If B wins

PA, PB, PB = 1/3 X 2/3 X 2/5 = 4/ 45

PB, PA , PB = 2/3 X 3/5 X 2/3 = 4 / 15

Total probability of conclusion of game in 3 matches

= 6/45 +6/45 + 4/45 +4/15 = 28/45

b )

For the game concluding in 2 matches , the probability are as follows

PA,PA = 1/3 X 1/3 = 1/9

PBPB = 2/3 X 2/5 = 4 / 15

Total probability

= 1/9 + 4/15 = 17/45

So PA = 1/9 / 17/45

= 5/17

5 0

2 years ago

if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?

Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 9 rolls, hence $n = 9$ .

Of the six sides, 2 are 3 or 4, hence $p = \frac{2}{6} = 0.3333$

The desired probability is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026$

$P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117$

Then:

$P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857$

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0

2 years ago

Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer. x(

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

In general (x, y, z) = (p ·cos s ·sin t, p· sin s· sin t, p · cos t) where p is radius

x(s, t)= 3 ·cos s ·sin t

y(s, t)= 3· sin s· sin t

z(s, t) = 3· cos t

Where, radius is 3, s ∈ [0,2π), and t ∈ [0, π]

4 0

1 year ago

2 Antonio is a set designer. He is gluing ribbon on 4 square and 2 triangular posters to be used as stage props in an upcoming p

Lana71 [14]

Answer:

89283

Step-by-step explanation:

8 0

2 years ago

Express the fraction<br> 1/3<br> as a decimal.

mihalych1998 [28]

Answer:

Step-by-step explanation:

1/3 as a decimal is 0.3333333 repeating

5 0

2 years ago

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