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Fynjy0 [20]
3 years ago
5

Supposed five plain hamburgers cost the same as three super burgers. Also suppose that one super burger cost $.30 more than one

cheeseburger wow one plain hamburger cost $.20 less than one cheeseburger. What would be the cost of one of each kind a burger
Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

Step-by-step explanation:

We have three conditions

(1) 5P = 3S

(2)  S = C + 0.30

(3)  P = C – 0.20                           Substitute (3) into (1)

=====

(4)   5(C – 0.20) = 3S                   Substitute (2) into (4)

      5(C – 0.20) = 3(C + 0.30)     Remove parentheses

         5C – 1.00 = 3C + 0.90       Add 1.00 to each side

                    5C = 3C + 1.90        Subtract 3C from each side

                    2C = 1.90                 Divide each side by 2

                      C = $0.95              Substitute C into Equation (2)

=====

                      S = 0.95 + 0.30

                      S = $1.25               Substitute C into Equation (3)

=====

                     P = 0.95 – 0.20

                    P = $0.75

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

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Combine like terms

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A good way to check if we did this correctly, is to add up the two angles. Because 180 + 50 = 180, we did this correctly.

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