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ladessa [460]
3 years ago
13

Brita has a monthly budget of x dollars. She spends $1,425 on her mortgage every month. One-third of her remaining budget is spe

nt on recreational activities. Which equation below can be used to determine the amount, in dollars, spent on recreational activities?
Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

$(x - 1425)/3

Step-by-step explanation:

Let total monthly budget be x

Amount spent on mortgage = $1425

Remaining balance after spending on mortgage = x - $1425

Amount spent on recreational activities = one-third of the balance

Expressing amount spent on recreational activities as an equation will give;

Amount spent on recreational activities = 1/3 of x - $1425

= 1/3 × ( x - $1425)

= ( x - $1425)/3

Hence the required equation is;

R = $(x - 1425)/3

R means recreational activities

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Answer:

Below.

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If its a right triangle it will obey the Pythagoras theorem.

17^2 = 289

11^2 + 15^2 = 121 + 225  = 346

- so NOT a right triangle.

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Answer:

5. 8/6x + 2

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4 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
At a football game between the Cougars and Wolves, there are 80,000 people. There are 20,000 Cougar fans at the game. All the ot
Naddika [18.5K]

Answer: 80%

80,000 = 100%

20,000 = 20%

100% - 20% = 80%

Always convert the main number into 100 and follow through with the other numbers

3 0
3 years ago
Read 2 more answers
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