The histogram is especially useful in comparing mean and median values of a variable. We have that 5.5+6+7+10+7.5+8+9.5+9+8.5+8+7+7.5+6+6.5+5.5=111.5 Since there are 15 values, their mean is 111.5/15=7.43 which is very close to the mean. We also have that 7 onservations are lower than 7.4 while 8 are bigger than 7.4; hence, the diagram is rather balanced and not left-skewed. We cannot tell immediately which one is larger since the values are too close. Any such random process can usually be approximated to a greater or smaller degree by a normal curve; the more points, the better. The histogram shows this (it is kind of a discrete normal curve); all points except 4 will be in this interval of bars.
4 pages Elena = 5 pages Jada
To figure out how many pages Jada reads if Elena reads 1, divide 5 by 4: 1.25. This means that for every 1 page Elena reads, Jada reads 1.25 pages.
So if Elena reads 9 pages, multiply 1.25 by 9: 11.25 pages that Jada reads.
For S pages read by Elena, this is a variable, so I’m assuming it means for every S pages, Jada reads 1.25S
Subtract the chance they have of winning from 100%:
100% - 14% = 86% chance of not winning.
(701+y)/(3+1)<200
(701+y)/4<200
701+y<800
y<99
So the most yards they can allow in the next game is 98 yards
