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pochemuha
3 years ago
5

In a plan for area codes, the first digit could be any number from 3 through 8, the second digit was either 0 or 4, and the thir

d digit can be any number but 0. With this plan, how many different area codes are possible?
Mathematics
2 answers:
dem82 [27]3 years ago
7 0

Answer:

I think the answer is 108.

gizmo_the_mogwai [7]3 years ago
3 0

Answer:

The answer is 108

Step-by-step explanation:

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KatRina [158]
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alexandr402 [8]
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3 years ago
Which of the following is a solution of the equation -5x + 2 = -13: answers: x=-9, x=75 x=3 x=-3
slamgirl [31]

Answer:

x= 3

Step-by-step explanation:

1. -5(3) + 2 = -13      

2. -15 + 2 = -13         <em>A positive times a negative will always equal a negative</em>

3. -13 = -13         <em>Whenever you add anything to a negative number, the                    </em>

<em>                            number becomes smaller   </em>

                     Ex:  -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, ...........

                           <em>Although the number itself becomes smaller, its value    </em>

<em>                             becomes bigger       </em>

Hope this helps.

7 0
3 years ago
Math please help !!!!!
bixtya [17]

Answer:

hope it helped

Step-by-step explanation:

2nd one is the answer

7 0
3 years ago
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