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3 years ago

What is the rate of increase for the function f(x)= 1/3(^3 sqr root 24)^2x

Mathematics

2 answers:

snow_lady [41]3 years ago

7 0

Answer:

4^3 square root 9

Step-by-step explanation:

Kazeer [188]3 years ago

3 0

You must simplify the function first until the exponent becomes a flat x. Step 1 Leave 1/3 only that is the value a, initial value. You are looking for the base Step 2 Deal with the parentheses. Factor 24 and you get 2 and the cube of 3. Step 3 Separate the exponent (2) (x) Step 4 Now square each term in parentheses 2 squared and cube 3 squared 2 2 will be 4, the other expression means cube of 3 times cube of 3 and that is cube of 9 Step 5 Your base should be (4 cube of 9)

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3 years ago

Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th

vivado [14]

The value of tangent theta is equal to the negative 1. At this value the value of secant theta is $\sqrt{2}$ .

<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

$\rm tan\theta=\dfrac{sin \theta}{cos \theta}$

Given information-

The value of tangent theta is equal to the negative 1.

$\tan \theta=-1$

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

$\rm tan\theta=\dfrac{sin \theta}{cos \theta}$

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

$\rm -1=\dfrac{sin \theta}{cos \theta}\\$

Simplify it further as,

$\rm -cos \theta=sin \theta$

When the value of cosine and sine theta is equal, then the angle exist in 4th quadrant with the value of $\dfrac{7\pi}{4}$ . Which extent to the $\sqrt{2}/2$ for the cosine function.

In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

$\rm \dfrac{1}{sec\theta}=\dfrac{\sqrt{2}}{2}\\sec\theta=\sqrt{2}$

Thus the value of secant theta is $\sqrt{2}$

Learn more about the tangent theta here;

brainly.com/question/29190

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2 years ago

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