First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them
12x^8/3x^3= 4x^8-3=4x^5
20^2x=20^x*20^x
m^5*m^-7=m^5-7=m^-2
Answer:
16 crates
Step-by-step explanation:
-This is a division problem.
-Let x be the number of crates that will fit in to the box car.
-To solve x, we divide the volume of the boxcar by the volume of one crate:

Hence, 16 crates will fit in the boxcar.
10/5÷5/5=2/1 or 2 so all you had to do was put the numbers over each other and simplify
1. 7x(x + 3)
7x(x) + 7(3)
7x² + 21
2. (7x + 1)(x + 3)
7x² + 21x + x + 3
7x² + 22x + 3
3. (x² + x)²
(x² + x)(x² + x)
x^4 + x³ + x³ + x²
x^4 + 2x³ + x²
Step-by-step explanation:
3x+8<4x−12
Move all terms containing x
to the left side of the inequality.
Tap for more steps...
−x+8<−12
Move all terms not containing x
−x<−20
x>20
Interval Notation:(20,∞)