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3 years ago

In parallelogram RSTU, what is SU?

1 answer:

5 0

Because S and U are the opposite vertices of the <span>parallelogram RSTU,
so SU is a diagonal of this </span>parallelogram.

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Find the equation of the line that passes through the points (6,14) and is parallel to y=-4/3x-1

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Answer:

y= -4/3 + 22

Step-by-step explanation:

y= -4/3x -1

14 = -4/3 (6) + b

14= -8 + b

22= b

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3 years ago

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3 years ago

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Monica [59]

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3 years ago

Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r

NeTakaya

$\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Explanation:</h2>

In this exercise, we have the following functions:

$r(x)=2x-1 \\ \\ s(x)=5x$

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

$(r-s)(x)$

That is, we subtract s(x) from r(x):

$(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}$

Second expression:

$(r\cdot s)(x)$

That is, we get the product of s(x) and r(x):

$(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}$

Third expression:

Here we need to evaluate:

$(r+s)(-2)$

First of all, we find the sum of functions r(x) and s(x):

$(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1$

Finally, substituting x = -2:

$(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0

3 years ago