Well first of all you got to show your answer.
She has = 5- 2 = 3
3 >= y * 0.55 > 0.55
5 > y > 1 (truncate in case of count)
Find the length of the field first. To do this, write a formula for the perimeter, P, of the field: P = 210 ft = 2(45 ft) + 2L.
Then 2L = 210 - 90 = 120, and L = 60 (feet).
The area of the field is thus WL = (45 ft)(60 ft) = 2700 sq ft
