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3 years ago

Write an expression for the model. Find the sum.

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

C)2+(-3);-1
If you look at the model you see it meets at zero both ways go to -1 and 2 but when you travel to -1 its -3 because you move backwards on the model

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What is 6/27 + 11/36 =

fgiga [73]

Answer:

0.527

Step-by-step explanation:

Divide 6 by 27 and that will get you to a long number like 0.2222222222 but we can shorten it to 0.222. After this you will divide 11 by 36 leading you to the answer of 0.3055555556 which again will shorten to 0.305. Add both of these solutions together and you will get 0.527 as your answer!

8 0

3 years ago

Read 2 more answers

The chief chemist for a major oil and gasoline production company claims that the regular unleaded gasoline produced by the comp

Svetradugi [14.3K]

Answer:

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621

Step-by-step explanation:

This is a normal distribution problem

The mean of the sample = The population mean

μₓ = μ = 4 ounces

But the standard deviation of the sample is related to the standard deviation of the population through the relation

σₓ = σ/√n

where n = Sample size = 100

σₓ = 1.2/√100

σₓ = 0.12

The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)

To do this, we first normalize/standardize the 4.3 ounces

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5

To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)

We'll use data from the normal probability table for these probabilities

P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621

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4 years ago

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit. The production grou

krok68 [10]

Answer:

We accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

Step-by-step explanation:

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit.

This means that the null hypothesis is: $H_0: \mu = 12$

The production group believes that the mean weight has changed.

This means that the alternate hypothesis is:

$H_a: \mu \neq 12$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

12 is tested at the null hypothesis:

This means that $\mu = 12$

They take a sample of 15 cans and find a sample mean of 12.05 ounces and a sample standard deviation of .08 ounces.

This means, respectibely, that $n = 15, X = 12.05, \sigma = 0.08$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{12.05 - 12}{\frac{0.08}{\sqrt{15}}}$

$z = 2.42$

Pvalue of the test:

We are testing if the mean is different from a value, which means that the pvalue is 2 multiplied by 1 subtracted by the pvalue of z = 2.42.

Looking at the z-table, z = 2.42 has a pvalue of 0.9922

1 - 0.9922 = 0.0078

2*0.0078 = 0.0156

What conclusion can we make from the appropriate hypothesis test at the .01 level of significance?

0.0156 > 0.01. This means that at the 0.01 level, we accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

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3 years ago

A contractor bought 10.8 ft squared of sheet metal. has used 2.1 ft squared so far and has $139.20 worth of sheet metal remaini

Anuta_ua [19.1K]

Answer:

7.1

Step-by-step explanation:

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3 years ago

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. Solve the system of equations using substitution. 3y = –x + 2 y = –x + 9 (3, 6) (20, –4) (–1, 8) (10, –1)

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