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Elena-2011 [213]
3 years ago
8

Help me with this plzzzzz I need to finish it rn so PLZZ help asp

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Answer:

1. 16π

2. 112π

3. 351.68

Step-by-step explanation:

Area of a circle = πr^2

Substitute...

=4^2π

=16π

To find the how much fluid it can hold, just basically find its volume. To do that, you mutiply the area of the base by the height. So...

16π*7=122π

You then just subsitute π by 3.14 so...

122(3.14)=351.68

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Sarah is carrying out a series of experiments which involve using mcreasing amounts of a chemical. In the
Marianna [84]

Sarah is carrying out a series of experiments which involve using increasing amounts of a chemical. In the  first experiment she uses 6g of the chemical and in the second experiment she uses 7.8 g of the chemical

(i)Given that the amounts of the chemical used form an arithmetic progression find the total amount of  chemical used in the first 30 experiments

(ii)Instead it is given that the amounts of the chemical used for a geometric progression. Sarah has a  total of 1800 g of the chemical available. Show that the greatest number of experiments possible satisfies the inequality: 1.3^N \leq 91 and use logarithms to calculate the value of N.

Answer:

(a)963 grams

(b)N=17

Step-by-step explanation:

(a)

In the first experiment, Sarah uses 6g of the chemical

In the second experiment, Sarah uses 7.8g of the chemical

If this forms an arithmetic progression:

First term, a =6g

Common difference. d= 7.8 -6 =1.8 g

Therefore:

Total Amount of  chemical used in the first 30 experiments

S_n=\dfrac{n}{2}[2a+(n-1)d] \\S_{30}=\dfrac{30}{2}[2*6+(30-1)1.8] \\=15[12+29*1.8]\\=15[12+52.2]\\=15*64.2\\=963$ grams

Sarah uses 963 grams in the first 30 experiments.

(b) If the increase is geometric

First Term, a=6g

Common ratio, r =7.8/6 =1.3

Sarah has a total of 1800 g

Therefore:

Sum of a geometric sequence

S_n=\dfrac{a(r^N-1)}{r-1} \\1800=\dfrac{6(1.3^N-1)}{1.3-1} \\1800=\dfrac{6(1.3^N-1)}{0.3}\\$Cross multiply\\1800*0.3=6(1.3^N-1)\\6(1.3^N-1)=540\\1.3^N-1=540\div 6\\1.3^N-1=90\\1.3^N=90+1\\1.3^N=91

Therefore, the greatest possible number of experiments satisfies the inequality

1.3^N \leq 91

Next, we solve for N

Changing 1.3^N \leq 91 to logarithm form, we obtain:

N \leq log_{1.3}91\\N \leq \dfrac{log 91}{log 1.3}\\ N \leq  17.19

Therefore, the number of possible experiments, N=17

3 0
3 years ago
31% of 40 estimate what is it please help​
chubhunter [2.5K]

31% of 40 is 12.4 exactly

7 0
3 years ago
Read 2 more answers
Look at the figure shown below: Which step should be used to prove that point A is equidistant from points C and B?
kobusy [5.1K]

Answer:

Combine points A with C and A with B. Consider ΔABD and ΔACD:


1. AD is common side, then  AD\cong AD;


2.   CD\cong BD  - given in the diagram;


3.  \angle ADB\cong \angle ADC .


By SAS Postulate,  \triangle ABD\cong \triangle ACD . Congruent triangles have congruent corresponding sides and congruent corresponding angles, so  AC\cong AB .


From this proof you can see that correct choice is option D (In triangles ABD and ACD, two sides and an included angle are equal.)



Step-by-step explanation:


3 0
4 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
Ann [662]

is this answer answer correct

option (C)

3 0
3 years ago
*EASY* Will mark brainest!!
3241004551 [841]

perpendicular! the slope of one is 1/8 while the slope of another is 8/1

5 0
4 years ago
Read 2 more answers
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