PLEASE HELP ME I BEG YOU
1 answer:
You might be interested in
Answer:
The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).
Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.
Step-by-step explanation:
Confidence Interval for the proportion:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
For the percentage:
Multiplying the proportions by 100.
The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).
Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.
Hi there!
The Eqn. is :-
1.5 (x + 4) - 3 = 4.5 (x - 2)
1.5x + 6 - 3 = 4.5x - 9
Combining the like terms :-
1.5x - 4.5x = - 9 - 6 + 3
- 3x = - 15 + 3
- 3x = - 12
x =
x = 4
Hence, the required answer is → x = 4
~ Hope it helps!
The Eqn. is :-
1.5 (x + 4) - 3 = 4.5 (x - 2)
1.5x + 6 - 3 = 4.5x - 9
Combining the like terms :-
1.5x - 4.5x = - 9 - 6 + 3
- 3x = - 15 + 3
- 3x = - 12
x =
x = 4
Hence, the required answer is → x = 4
~ Hope it helps!