Slope intercept form is: y = mx + b
Isolate the y. First subtract 10x from both sides
10x (-10x) + 2y = 8 (-10x)
2y = -10x + 8
Isolate the y. Divide 2 from both sides and <em>all</em> terms.
(2y)/2 = (-10x + 8)/2
y = -5x + 4
y = -5x + 4 is your slope intercept form answer.
hope this helps
Answer:
C.
Step-by-step explanation:
Answer:
195
Step-by-step explanation:
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =![3x^2 -2x +1](https://tex.z-dn.net/?f=3x%5E2%20-2x%20%2B1)
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.