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andreev551 [17]
4 years ago
8

Write in standard form y-3x=1

Mathematics
1 answer:
kvasek [131]4 years ago
5 0
The standard form is y=mx+b.
With y-3x=1, you're trying to get y by itself.
Start with adding 3x to both sides to get y=3x+1
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Isosceles triangle ABC has a perimeter of 96 centimeters. The base of the triangle is and measures 24 centimeters.
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Question 9<br> Expand and simplify (2x-7)(3x-8).
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Answer:

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Use the distance formula to find the area of the rectangle
nasty-shy [4]

Answer:

Therefore Area of Rectangle is 50 unit².

Step-by-step explanation:

Given:

Let the vertices of a Rectangle be

A ( -1 , 7)

B ( 4 , -3)

C ( 0 , -5)

D ( -5 ,5)

To Find:

Area of Rectangle ABCD = ?

Solution:

First we will find the Length and Width of Rectangle by Distance Formula ,

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting the values we get

l(AB) = \sqrt{((4-(-1))^{2}+(-3-7)^{2} )}

l(AB) = \sqrt{((5)^{2}+(-10)^{2} )}\\l(AB)=\sqrt{125}=5\sqrt{5}\ unit

Similarly for BC we will have,

l(BC) = \sqrt{((0-4)^{2}+(-5-(-3))^{2} )}\\l(BC)=\sqrt{20}=2\sqrt{5}\ unit

Now

Length=AB =5\sqrt{5}\ unit\\Width=BC=2\sqrt{5}\ unit

Now Area of Rectangle is given by

\textrm{Area of Rectangle}=Length\times Width

Substituting the values we get

\textrm{Area of Rectangle ABCD}=5\sqrt{5}\times 2\sqrt{5}=10\times 5=50\ unit^{2}

Therefore Area of Rectangle is 50 unit².

4 0
3 years ago
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