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ale4655 [162]
3 years ago
14

BC is tangent to circle A at B and to circle D at C. AB= 10 BC= 21 DC= 8 find AD to the nearest tenth

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0
The attached diagram is an interpretation of the question.
If there are other details, please post.

The distance AD is found by Pythagoras theorem, with 
AD=sqrt(BC^2+(AB-DC)^2)=sqrt(21^2+2^2)=sqrt(441+4)=sqrt(445)
=21.095 (to the third decimal place)

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D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=
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Answer:

<h2>x = 28</h2><h2>CE = 132</h2><h2 />

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

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2x + 10 = 3x - 18

2x - 3x = -18 - 10

-x = -28

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CE = 2x + 10 + 3x - 18

CE = 2(28) + 10 + 3(28) - 18

CE = 56 + 10 + 84 - 18

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4 years ago
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Answer:

\large\boxed{y=\dfrac{4}{5}x-6}

Step-by-step explanation:

The slope-intercept form of equation of a linear function:

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3 years ago
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Answer:

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Step-by-step explanation:

The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.

The question given says that <em><u>Nancy</u></em> is <em><u>pushing</u></em> the statue with a force of<em><u> 120 N at a 60° angle to the horizontal</u></em> and <em><u>Harry</u></em> is <em><u>pulling</u></em> the statue with a force of <u><em>180 N at a 40° angle with the horizontal</em></u>.

With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.

The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.

F= (120 N cos 60°) + (180 N x cos 40°)

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