All categories

3 years ago

BC is tangent to circle A at B and to circle D at C. AB= 10 BC= 21 DC= 8 find AD to the nearest tenth

Mathematics

1 answer:

Andrei [34K]3 years ago

4 0

The attached diagram is an interpretation of the question.
If there are other details, please post.

The distance AD is found by Pythagoras theorem, with
AD=sqrt(BC^2+(AB-DC)^2)=sqrt(21^2+2^2)=sqrt(441+4)=sqrt(445)
=21.095 (to the third decimal place)

You might be interested in

Using the new unit you have defined, rewrite the debt for years 1900, 1930, 1960, and 2000.

-BARSIC- [3]

Answer:

1789

it is so easy looser

3 0

3 years ago

The number of employees for a certain company has been decreasing each year by 4%. If the company currently has 710 employees a

Arte-miy333 [17]

Answer:

Answer is A

Step-by-step explanation:

4 0

2 years ago

Plz urgent <br>inequalities

solmaris [256]

Answer:

X>-4

Y>-18

X>-7

I hope this helps

3 0

2 years ago

☆☆10 points☆☆<br>BRAINLIEST IF CORRECT ANSWER!

zavuch27 [327]

Answer:

$this \: paper \: needs \: to \: be \: folded \: \\ \underline{ \boxed{twice \: (2 \: times)}}$

Step-by-step explanation:

$let \: the \: let \: the \: length \: be \to \: x \\when \: folded : it \: becomes \to \: \frac{x}{2} \\hence : \to \\ 93.5 \times \frac{x}{2} = (93.5 - 1) \\ 93.5x = 2(93.5 - 1) \\ 93.5x = 2 \times 92.5 \\ 93.5x = 185 \\ x = \frac{185}{93.5} \\ \boxed{x = 1.9786096257 }\\$

6 0

2 years ago

Solve 1/2cot(x)>=1/2 over 0<=x<=2pi

RSB [31]

9514 1404 393

Answer:

(0, π/4] ∪ (π, 5π/4]

Step-by-step explanation:

Multiplying by 2 gives ...

cot(x) ≥ 1

The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.

x ∈ (0, π/4] ∪ (π, 5π/4]

_____

(a, b] is interval notation for a < x ≤ b

3 0

3 years ago