BC is tangent to circle A at B and to circle D at C. AB= 10 BC= 21 DC= 8 find AD to the nearest tenth
1 answer:
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Answer:
x = 3√7
Step-by-step explanation:
From the right triangle given in the picture,
Altitude or height of the triangle (AD) = x
Base or hypotenuse of the given triangle (BC) = 16
Length of segment BD = 16 - 7 = 9
By using geometric mean theorem in the given triangle,
(AD)² = (BD)(CD)
x² = 9×7
x = √63
x = 3√7
