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maksim [4K]
3 years ago
5

What is the tangent ratio of KJL? (Question and answers provided in picture.)

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:

Option (1)

Step-by-step explanation:

The given triangle JKL is an equilateral triangle.

Therefore, all three sides of this triangle will be equal in measure.

Side JK = JL = KL = 48 units

Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.

By applying tangent rule in ΔJML,

tan(∠KJL) = \frac{\text{Opposite side}}{\text{Adjacent side}}

                = \frac{\text{LM}}{\text{JM}}

                = \frac{\text{LM}}{24}

Since, Sin(K) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

Sin(60)° = \frac{\text{LM}}{48}

\frac{\sqrt{3}}{2}=\frac{\text{LM}}{48}

LM = 24√3

Now, tan(∠KJL) = \frac{\text{LM}}{24}

                          = \frac{24\sqrt{3} }{24}

Therefore, Option (1) will be the answer.

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