That doesn’t make sense? Do u mean like guess on what their hair color and style could be
How to find the area of a parallelogram is length times height. 12 times what gets you to 60? 5 does. 12 times 5 is 60.
HEIGHT: 5
The trick is to exploit the difference of squares formula,

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

Whatever you do to the denominator, you have to do to the numerator too. So

Expand the numerator:






So we have

But √12 = √(3•4) = 2√3, so

(X^2+8x)-(x-8)=0
x(x+8)-1(x+8)=0
(X-1)(x+8)=0
X= 1
X= -8
1.
In line with the test each person who came into interaction
with the infected person will become infected also. With this information, the
calculation would be: 9 people each day for 7days would be equivalent to 9 x 7
which equals 63 people.
2.
Here were 7 other people in the experiment if patient
zero is left out. If each person intermingled with 6 different people every day
in 7 days then the calculation would be: 7 people infected x 6 new people = 42
infected people each day
42 new people every day x 7 days = 294
infected persons.