X=-2 Plz I need it plz

Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation

mash [69]

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

5 0

3 years ago

Is 32.5 greater or less than 30.8 PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)

ivann1987 [24]

Answer:

32.5 is greater than 30.8

6 0

3 years ago

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60:92=105:n what is n?

PIT_PIT [208]

Hey! I'll provide you the answers!

First you want to simplify the equation using cross-multiplication.

$15n = 2415$

Finally, you would want to divide both sides by 15.

n = 161

5 0

3 years ago

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You buy the following materials for the new extension. Calculate the cost of the bricks and cement and then work out the total c

bogdanovich [222]

Answer:

Cost of sand = £150

Cost of bricks = £157.5

Cost of cement = £134

Total cost = £441.50

Step-by-step explanation:

We are given that:

2 tonnes of sand is for £75.00 per tonne,

20 bags of cement are for £6.70 per bag,

350 bricks at 45p each,

So, 2 tonnes of sand at £75.00 per tonne = 2 * £75.00 = £150.00

20 bags of cement at £6.70 per bag = 20 * £6.70 = £134.00

350 bricks at 45p each = 350 * £0.45 = £157.50

Therefore, the total cost of all the materials = £150 + £134 + £157.5 = £441.50

7 0

3 years ago

76. Currently, your savings for each month is capped at $400. If you start investing all of this into a savings plan earning 1%

Alexxandr [17]

Answer:

10 years and 10 months.

Step-by-step explanation:

The annually interest rate (ia) can be converted by monthly (im) by the equation:

(1 + im)¹² = 1 + ia

(1 + im)¹² = 1 +0.01

(1 + im)¹² = 1.001 (putting ln in both sides)

ln(1 + im)¹² = ln1.001

12*ln(1 + im) = 1.0x10⁻³

ln(1 + im) = 8.33x10⁻⁵(applying "e in both sides)

$e^{ln(1 + im)} = e^{8.33x10^{-5}}$

1 + im = 1.00083

im = 0.00083 = 0.083%

For a investimenting, the final amount (A) can be calculated by:

$A = R*(\frac{(1+i)^n-1}{i} )$

Where R is the amount invested per month, i is the interest, and n the number of months:

160000 = 400 * $\frac{(1 +0.00083)^n - 1}{0.00083}$

$\frac{(1 +0.00083)^n - 1}{0.00083}$ = 400

1.00083ⁿ - 1 = 0.332

1.00083ⁿ = 1.332 (applying ln in both sides)

n*ln1.00083 = ln1.332

8.3x10⁻⁴n = 0.2867

n = 345.4 months

345.4 months *1 yea12 months = 10 years and 10 months.

7 0

3 years ago

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