<span>The fraction of baked goods not sold is 6/10. The numerator is the number of left over baked goods (10-4 -6) and the denominator is the total loaves of bread (10). An equivalent fraction is 12/20. This was obtained by multiplying the original fraction by two (6 x2 = 12 and 10 x2 =20).</span>
Answer:
Area = 160 cm²
Perimeter = 55.31 cm
Step-by-step explanation:
Applying,
Area of the figure = area of the rectangle- area of the triangle
A = lw+bh/2............... Equation 1
From the question,
Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm
Substitute these values into equation 1
A = (16×12)-(8×8/2)
A = 192-32
A = 160 cm²
Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/
Applying pythagoras theorem to get /FG/
FG² = GE²+EF²
FG² = 8²+8²
FG² = 64+64
FG² = 128
FG = √128
FG = 11.31 cm
Therefore,
P = 16+12+4+8+11.31+4
P = 55.31 cm
Answer:
A
Step-by-step explanation:
50 percent is 50/100 and you are trying to find x which is half of 70. A would make the most sense. X should =35
Answer: 1513.
Step-by-step explanation:
This is just another way to write subtraction! So just write it as a subtraction problem.
1576-63 = 1513 ^^
In "slope-intercept form"
y = mx +b
the value "m" is called the slope, and the value "b" is called the intercept.
There is another form for the equation of a line, called "point-slope form".
y = m(x -h) +k
where m is still the slope and (h, k) correspond to the (x, y) of the point.
If you write the equation of your line in this "point-slope form", it is easily manipulated to be in the "slope-intercept form".
Fill in
m = (-3/5)
h = -4
k = 0
y = (-3/5)(x -(-4)) +0
Now, you simplify this by using the distributive property.
y = (-3/5)x -(3/5)*4
y = (-3/5)x -12/5 . . . . . . . . . the desired equation
_____
Your understanding of math improves immensely when you become familiar with the terminology. A lot of the rest of it is pattern matching--identifying the parts of one expression that correspond to the parts of another one.
(You will see another version of the "point-slope form", but I find this one the easiest to use for manipulating the equation to other forms.)