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3 years ago

A gasoline pumps delivers 4 2/5 gallons of gas per minute how many minutes will it take to fill a gas data old 16 1/2 gallon

1 answer:

7 0

4*2/5 = 22/5
16*1/2 = 33/2

22/5 ............. 1 min
33/2 ..............x min

x = 33/2 : 22/5 = 33/2 x 5/22 = 165/44 = 3,75 min

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60 yards back

Step-by-step explanation:Mutiply 4 and 15

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3 years ago

The figure shows two intersecting lines and measures of the resulting angles.

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3 years ago

Part 6

Deffense [45]

Answer:

Part 1) The volume of each beam is $1,858.88\ ft^{3}$

Part 2) You can fill $26\ beams$

Part 3) Yes, the amount of sand left over is $1,669.12\ ft^{3}$

Step-by-step explanation:

Part 1) What is the total volume of each beam?

The volume of a cylinder is equal to

$V=\pi r^{2} h$

we have

$h=37\ ft$

$r=8/2=4\ ft$ ----> the radius is half the diameter

assume

$\pi=3.14$

substitute the values

$V=(3.14)(4)^{2} (37)$

$V=1,858.88\ ft^{3}$

Part 2) How many beams can you fill with this sand?

we know that

You are given a container with a 50,000 sq ft of sand for your beams

<em>Note</em> Is a 50,000 cubic foot of sand instead of 50,000 sq ft of sand

Divide the total volume of sand by the volume of each beam to obtain the number of beams

$50,000/1,858.88=26.9\ beams$

Round down

$26.9=26\ beams$

Part 3) Will you have any sand left over? If so how much?

yes

$50,000-26(1,858.88)=1,669.12\ ft^{3}$

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3 years ago

Situation B: Suppose that 40% of Missourians favor increasing the minimum wage. Twelve Missourians are selected at random and as

yulyashka [42]

Answer:

14.19% probability that exactly three of the twelve support the increase.

Step-by-step explanation:

For each Missourian, there are only two possible outcomes. Either they support the increase, or they do not. The probability of a Missourian supporting the increase is independent of other Missourians. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$