According to a study, an average of six cell phone thefts is reported in San Francisco per day. Assume that the number of report ed cell phone thefts per day in the city follow the Poisson distribution. What is the probability that four or five cell phones will be reported stolen tomorrow?
1 answer:
Answer:0.29
Step-by-step explanation:
An average of six cell phone thefts is reported in San Francisco per day. This means our mean value, u = 6
For poisson distribution,
P(x=r) = (e^-u×u^r)/r!
probability that four cell phones will be reported stolen tomorrow=
P(x=4)= (e^-6×6^4)/4!
= (0.00248×1296)/4×3×2×1
= 3.21408/24=
0.13392
P(x=5)= (e^-6×6^5)/5!
= (0.00248×7776)/5×4×3×2×1
= 19.28448/120
= 0.1607
probability that four or five cell phones will be reported stolen tomorrow
= P(x=4) + P(x=5)
= 0.13392 + 0.1607
= 0.294624
Approximately 0.29
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Answer:
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Step-by-step explanation:
First find g:
g(x) = 3x-5
g(x) = 3(4) - 5
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Plug in:
f(g(4))
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Answer:
B) μD = 0.60 ± 0.10(1.397)
Step-by-step explanation:
The confidence interval is given by:
Where
MD=60
n=9
df=n-1=8
Then the confidence interval is
μD=0.60±1.397*(0.3/√9)
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