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saveliy_v [14]
3 years ago
10

A construction company is starting to build a new house. They need to put tape around the site to begin. The new home site is 20

meters wide by 40 meter long rectangle. The company already has 100 meters of tape. How much more tape does the company need to tape the site?
Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0
Answer: They need 20 more meters of tape.

This is because they are putting tape around the perimeter. To find the perimeter you add up each side.

This is shown like this

20+20+40+40=120meters.

But the question is asking how many more meters of tape does the company so we subtract the amount of tape they already which is 100meters from 120meters.

So it can be written like this

120m -100m = 20meters of tape

Answer: the company needs 20 more meters of tape.

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Answer:

y = -6

Step-by-step explanation:

Step 1: Define

8x - 9y = -50

x = -13

Step 2: Substitute and solve for <em>y</em>

8(-13) - 9y = -50

-104 - 9y = -50

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<em><u>Question:</u></em>

Ana participated in a charity walk. She raised $0.25 for each 1/2 mile that she walked.The first day Ana walked 11 miles.The second day, she walked 14 miles.How much money did Ana raised?

<em><u>Answer:</u></em>

Ana raised $ 12.5

<em><u>Solution:</u></em>

From given question,

First day walk = 11 miles

Second day walk = 14 miles

<em><u>Let us first calculate the total distance she walked</u></em>

Total distance = first day walk + second day walk

Total distance = 11 + 14 = 25 miles

Thus she walked for 25 miles

Given that,

<em><u>She raised $0.25 for each 1/2 mile that she walked</u></em>

\frac{1}{2} \text{ mile} = 0.25 \text{ dollars }

Therefore, for 1 mile we get,

\frac{1}{2} \times 2 \text{ mile} = 0.25 \times 2 \text{ dollars }\\\\1 \text{ mile } = 0.5 \text{ dollars }

Now calculate for 25 miles

25 \text{ mile } = 25 \times 0.5 = 12.5 \text{ dollars }

Thus she raised $ 12.5

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Step-by-step explanation:

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Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

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Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

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