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hoa [83]
2 years ago
5

What is the percent of change from 500,000 to 20,000?

Mathematics
2 answers:
photoshop1234 [79]2 years ago
8 0

Answer:

96 decrease

Step-by-step explanation:

5000000-20000=

480000/500000 x 100

96

96% decreased

ss7ja [257]2 years ago
8 0

Answer:

I think it may be 96% decrease

please tell me if im wrong ^^

Step-by-step explanation:

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Answer:

You have not added a picture soi can not help answer this question.

Step-by-step explanation:

Add the picture by either taking a photo or screenshot of the question then upload it.

3 0
2 years ago
I need help, please​
tensa zangetsu [6.8K]

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

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4 0
2 years ago
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What is the volume of a rectangular prism with a length of 4 yards, width of 3 yards and height of 6 yards?
Lunna [17]
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4 0
3 years ago
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
1/2y^2(6x+2y+12x-2y) is equivalent
vazorg [7]
The answer is 9y^2x(the 2 goes on top were the arrow is ) Hope this was helpful!
3 0
3 years ago
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